题目内容：
A.Y2=Acos[2πt-π/2]
B.Y2=Acos[2πt-π]
C.Y2=Acos[2πt+π/2]
D.Y2=2Acos[2πt-0.1π]
参考答案：
答案解析：
选择题：A.Y2=Acos[2πt-π/2] B.Y2=Acos[2πt-π] C.Y2=Acos[2πt+π/2] D.Y2=2Acos[2πt-0.1π]
- 题目分类：公用设备师
- 题目类型：选择题
- 号外号外：注册会员即送体验阅读点！
A.Y2=Acos[2πt-π/2]
B.Y2=Acos[2πt-π]
C.Y2=Acos[2πt+π/2]
D.Y2=2Acos[2πt-0.1π]