题目内容：
直线mx-y+n=0过点(2，2)，则4m+2n的最小值为（ ）．
A．1 B．2
C．2.3
D．4
参考答案：
答案解析：
单选题：直线mx-y+n=0过点(2，2)，则4m+2n的最小值为（ ）．
- 题目分类：小学数学
- 题目类型：单选题
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B．2
C．2.3
D．4
B．2
C．2.3
D．4
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第44题应选：
第44题应选：A．calls B．called C．has called
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第43题应选：A．could B．would C．should
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